Collision Theory and Reaction Mechanism

Hello everyOne, soRry if this blog is late...

What we did in class this morning is that Ms. K helped us to answer all the questions on the sheets the she gave to us. about potential energy diagrams and factors affecting rate. Just look at the slideshow for the answers that you didnt get..

*It sticks to my mind that the addition of CATALYST increase the rate and the activation energy become lower, like what happened to the experiment of ms. K last wednesday.

Then, she gave a new sheet about Collision and Reaction Mechanism and its glad that she explained it very clear... Like theres some new terms that we need to remember, like the

->BIMOLECULAR it means that its a combining of two particles.
->SIMPLE REACTION is the reaction which place in one elementary step.
->COMPLEX REACTION is the reaction which take place in more than one step..
Hint: all Complex Reaction contain at least one reaction intermediate.
->REACTION INTERMEDIATES products of one reaction that immediately become reactants in another reaction.
->MECHANISM is the steps in which a reaction occurs.
->RDS or RATE DETERMINING STEP the step with the slowest rate.

Ms. K also left us an assignment, just to remind you guys its assignment #4.
I didnt wrote too much because all the details is in the slideshow, just look at it.
Thenkzz...
The next scribe would be phoebes3...

Neutralization, Titration, and Concentration

Well, I' m a scribe for today...
Actually, I'm a lil' bit confused about the formula that Ms. K gave to us...

Well, Before we continue our Titration Lab from yesterday, Ms. K. explained and gave some examples for us about Neutralization,Titration, and Concentration. She gave us a sheet that is really helpful, because it has a lot of information and this sheet explained the step by step...
Here's the notes that i've got...

Step #1: Balance equation: H2so4(aq) + Na OH(aq) -> Na2 SO4 + H2O
= H2SO4 + 2Na OH(aq) -> Na2 SO4 + 2H2O

Step #2: The formula is: n=CxV
0.0054mol H2SO4 x 2 mol NaOH Then, cancel both sulfuric acid, then do the calculation.
1 mol H2SO4

Step #3: The formula is C=n/V
0.0108 mol = C= 0.360 mol/L
0.0300L

After Ms.K. explained about this, she let us continue our Titration Lab. and reminded us about our TEST tomorrow....

So folks.... Don't forget about the First TEST tomorrow!!!
Good Luck to all of us!!!

I think it's phoebes3' s turn!!! Good daY!!!