Scribe Post

Sorry everyone I didn't realize that I was the scribe for Tuesdays class.

Today was the last day to work on the Test Tube Mystery Lab.

I will complete this scribe later on.

The scribe for Wednesday's class is Jefferson :)

Feb.28 Notes

These are today's notes from class

Test Tube Mystery Lab

Hi guys, I'm the scribe for today's class since i wasn't there on Friday. We started to work on the test tube mystery lab, which we have to identify the 12 unknown solutions that are given in the hand-out we got last week from Ms. K. It tells us what we have to do before starting the lab, what materials we need for the lab and from what we have learned from the past 2, 3 weeks, we should know how to observe it. We also can go on the net to find out or get more information for the lab. Each group only have to hand in one lab write-up explaining how you determined the identity of each test tube, also include the observations (any precipitates formed) with the net ionic equations. Anyways we'll also have tomorrow to finish the lab. Goodluck everyone! :)

The next scribe will be crystal.

Feb23: Oxidation and Reduction

hello, last friday we learned about oxidation and reduction.
previously we learned that there are 5 type of reactions but on friday we learned that there are only two different families of chemical reactions:
1-those that don't have exchange of electrons-->non-redox reactions
2-those that do have exchange of electrons-->redox reactions

*when a substance lost/gave up its electrons it's an oxidation reaction:
Al(s) --> Al³⁺ + 3 electrons

*when a substance gains electrons it's called a reduction reaction:
Al³⁺ + 3 electrons --> Al(s)

to remember those key points we could use:
Oxidation
Is
Losing

Reduction
Is
Gaining
(OIL RIG)
or:
Losing
Electrons
Oxidation

Gaining
Electrons
Reduction
(Leo Ger)

also an important point is that Oxidation and reduction always occur at the same time, so that the number of electrons gained in a reaction is always equal to the electrons lost.
:. to keep track of the loss and gain of electrons in a reaction we use Oxidation States(imaginary charge an atom would have if both the electrons in an electron pain belonged to the most electronegative element of that pair)
Oxidation numbers are positive and negative numbers that are related to an atom's oxidation state.

the most important part of the lesson was knowing the 9 rules applying to the concept.
DUH RULES:
1-The oxidation number of an atom in an uncombined element is zero.
ex. O₂

2-the SUM of the oxidation numbers of the elements in any neutral molecule is zero.
ex. MgCl₂
+2 + (-1 x 2)= 0

3-the sum of the oxidation numbers of the elements in any ion is equal to the charge on the ion.
ex. NO₃^-1
+5 + (-2 x 3) = -1

4-in compounds the oxidation number of many elements corresponds to their position on the periodic table.
a)elements in Group 1A are always {+1}
ex. H , Li, Na, K, Rb, Cs, Fr

b)the alkaline earth metals are always {+2}
ex. Be , Mg, Ca, Sr, Br, Ra

c)aluminum is always {+3} and zinc is always {+2}

d)halogens are almost always {-1}
ex. F , Cl, Br, I, At

e)Hydrogen always has an oxidation number of {+1} when it's combined with non metals.
ex. HCl

f)oxygen has an oxidation number of {-2} in most compounds (exception:in peroxides where it is -1, ex. H₂O₂ (hydrogen peroxide)
ex. SO₂ S is +4 and O is -2

i guess that's all!
i think we have a scribe for today, so i won't pick.

Test Results...

Well im scribe today!!i hate doing This...ahh....well um Ms. K gave the test results awhile ago and it was 38 marks but at least i got a good mark...well um the question that most of us got the wrong answer was question number 8. and the question was ...You have two solutions.One is Green and the other is pink.When you mix the solutions together,a precipitate forms.the remaining solution is pink.Suggest two compounds that could give you these results.
And the answer for this question was
NiCl2 + Mn(OH)2 -----Ni(OH)2(s) + MnCl2

in which Nickel hyrdoxide gives you a precipitate and Manganese Chloride gives you the pink solution

And on Monday and Tuesday we will be doing some test about identifying compounds

and we will be observing and doing some stuff like...

1.Colour of the solutions(don't forget to put some o)

2.Odour(again)-waft vapours to your nose,don't smell it directly

3.flame test on tuesday

4. solubility of ions-ppt. forms

hydroxides-white ppt.

5.Litmus paper-if blue to red then it is acid and if it is red to blue,it is base

*reminder:don't contaminate your solutions and use only one pippette in each solutions..

keikei

the next scribe will be Jess

TEST DAY!!!

hi everyone,

today was our very first test for chemistry 12. Hooray!!!!!

how was the test?

If you didn't bother to look and answer Ms. Kozoriz's hand outs, then you'll probably have had a hard time with the test.

the contents of the test is pretty much everything that we did in the previous week.

In my own opinion it was ok.

But I did have a problem with the mole part that is worth 4 marks, i think i got that one wrong.
I hope ms. K would be generous to at least give 1 mark for effort on trying to solve the problem.

so good luck to us all. and i hope everyone did well for this exam.

i really don't know what else to say.....

special date: FEB 26-27: get ready to name 12 chemicals.
question: are we suppose to pass a written report/research on the Test Tube Mystery Lab?

our next scribe is forgHa_baybhie

Neutralization, Titration, and Concentration

Well, I' m a scribe for today...
Actually, I'm a lil' bit confused about the formula that Ms. K gave to us...

Well, Before we continue our Titration Lab from yesterday, Ms. K. explained and gave some examples for us about Neutralization,Titration, and Concentration. She gave us a sheet that is really helpful, because it has a lot of information and this sheet explained the step by step...
Here's the notes that i've got...

Step #1: Balance equation: H2so4(aq) + Na OH(aq) -> Na2 SO4 + H2O
= H2SO4 + 2Na OH(aq) -> Na2 SO4 + 2H2O

Step #2: The formula is: n=CxV
0.0054mol H2SO4 x 2 mol NaOH Then, cancel both sulfuric acid, then do the calculation.
1 mol H2SO4

Step #3: The formula is C=n/V
0.0108 mol = C= 0.360 mol/L
0.0300L

After Ms.K. explained about this, she let us continue our Titration Lab. and reminded us about our TEST tomorrow....

So folks.... Don't forget about the First TEST tomorrow!!!
Good Luck to all of us!!!

I think it's phoebes3' s turn!!! Good daY!!!

Neutralization Reaction

Ew... I'm scribe today. Um.... This note seemed very short. Here we go....
First of all, We were talk about how to names the Acids . Here's the notes :
Salt Name (s)* Acid Names
HBr Hydrogen Bromide Hydrobromic Acid
HI Hydrogen Iodide Hydroiodic Acid
HF Hydrogen Fluoride Hydrofluoric Acid
H2S Hydrogen Sulfide Hydrosulfuric Acid

* s : solid

- Root Acid _Ternary:
HIO4 Periodic Acid
HIO3 Iodic Acid
HIO_2/ Iodus Acid
HIO Hypoiodous Acid
HI Hydroiodic Acid

Next , Ms. K explained and gave an some examples for us about Neutralization Reaction. I liked the sheets we got :) . After that, we went through the questions 1 to 5 in Neutralization Reaction WorkSheet. Most of them were balanced equation and naming the Acid.(^_^ It's pretty COol....).
Finally, we were doing Titration Lab and we'll continue tomorrow . So , yah....that's all the information for today.
- One more important thing . We will have a test on Wednesday,21 /2007 . YOU GUYS. ....DON'T FORGET <^_^>. Good luck to everyone (*)

I think Rhiyo will be Tuesday's scribe ^.^ . Have Fun.

The Missing Scribe...

Haha. Today I wasn't in class... Surprisingly enough.. I was on a Field trip. And when I got back to school, I couldn't get back to class, cause there was a substitute... Hurray?? Well suffice to say, I got an insider taking notes for me. So here we go. Haha.

Today in class there was a substitute. Hurray!!! Blah. I wasn't there. So there. Today supposedly, the sub handed out worksheets. Mostly on acids and bases. And then we handed them in. He then talked in a weird accent and said allot of stuff relating to the topic at had for the day. Wow mostly review. The end.

Oh yeah... The next scribe is..... Beautiful Soul. I wonder who that is...

Solution Detective Lab

We started off by going over question 2 from yesterdays "prelab(?)".

the solutions to it was:

1) AgNO₃

2) NaI

3) CoSO₄

4) Bacl₂

After that we did our our lab where we had to pretended to be detectives to figure out what the 4 mistery solution were. Each group( of 2) had their own set of 4 solutions where one had a color while the other three were colorless.

After that was completed and handed in, Mrs K handed us a lab which we will be doing during the 26-27. Instead of identifying 4 solutions, we have to identify 12 solutions. this is not a group lab so we have to do this individually. We have to do estensive research on the lab And write up how we're going to approuch this lab, ei how are we going to identify 12 solutions

For those of you who were absent, i've taken the liberty of uploading the lab assignment online. so you can download it from the link provided.

Test Tube Mystery

The next scribe is Ricky

Which solution is which?

The last two days in class were spent on the following:
(a) using a solubility chart to determine which solutions would form precipitates
(b) writing molecular equations for double displacement (or replacement) reactions
(c) writing total (or complete) ionic equations and net ionic equations
(d) finding out the identity of solutions by using the colour ion charts and the solubility charts

Helpful Hints for Writing Molecular, Total Ionic and Net Ionic Equations
(1) Balance the molecular equation and write the states of the substances (g, l, s, aq).
(2) Substances that are dissolved in water (aqueous) are written as ions; all other substances stay in molecular form (example: CO_2(g))
(3) Cancel out the spectator ions (ions that don't take part in the reaction) and write the net ionic equation.

Solubility Rules

From the homework given on Friday, there was a question about combustion. This means that oxygen gas (O₂) is involved as a reactant in the chemical reaction.

The class then did an experiment to determine which cations ions were soluble or insoluble with certain anions. Half of the class did set A and the other half of the class did set B. Somehow the solutions containing (Na⁺), (K⁺), and (Cl^-) were contaminated. These ions don't form precipitates :((

The First Week

Some hints were given this week as we reviewed grade 11 chemistry.
(a) Writing formulas-all positive charges and all negative charges equal zero
(b) Putting in the states of the substances: is it a solid, liquid, gas, or is it dissolved in water (aqueous)
(3) Negative ions are named by adding -ide to the root name; examples: chlorine becomes chloride (Cl^-), and sulfur becomes sulfide (S^-2)
(4) -ate and -ite are ions that contain oxygen