Ms. K was not around and we have a substitute, Ms. McQueen. We just went over the Kinetics assignment # 4 and she gave us some hand outs on RATE LAW.
So for those who missed class and wasn't able to get the answer to the Kinetics assignment #4, here you go:
1. 2H2O2 ----> 2H2O + O2
2. (a) 2P + Q + S ----> R + T + W
(b) Slow
(c) Both P & Q are present in the rate limiting step and since S is not in the rate limiting step it does not affect the rate of of the net reaction. Only the reactants in the rate-
limiting step will significantly affect the rate of the reaction.
3. (a) The RDS is step 1 : C6H6 + NO2+ ----> C6H6NO2+
Because it's the slow reaction.
(b) C6H6 + NO2+ ----> C6H6NO2+ + H+
(c) H2SO4 is introduced in step 2 and is unchanged at the end of the reaction. H2SO4 is most likely a catalyst sine it speeds up the reaction but is unchanged at the end of the reaction
(d)
Step 1 Ea 1 Increase (longest)
Step 2 Ea 2 Decrease (smallest)
Step 3 Ea (small)
4. (a) The rate Increase
(b) p + 3Q ----> Z + Y
(c) The RDS is Step 2: A + 2Q ----> X + Y because it has the lowest rate of reaction.
so thats about it. see you all monday.....
next scribe is forgHa_baybhie
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